[R] zoo object: replace NAs from another zoo object

[Gabor Grothendieck]

An example that included input and output would help.  I'll take a guess but if
that's not it please clarify and provide that.

Also its helpful if you can provide the data in easily copied form
using dput(z).

I will assume that time(New) is a superset of time(Old) and "put them in" means
replace the values in Old with those from New so that Old should be the same
shape and have the same times before and after.

> library(zoo)
> Old <- zoo(matrix(1:10, 5))
> New <- zoo(matrix(c(NA, 12:16), 3))
> New.omit <- na.omit(New)
> window(Old, time(New.omit)) <- New.omit
> Old

1  1  6
2 12 15
3 13 16
4  4  9
5  5 10


On Thu, Mar 13, 2008 at 6:47 PM, Timothy W. Hilton <twh142 at psu.edu> wrote:
> Hello,
>
> I have two zoo objects, new and old, indexed by chron objects.  Their structure is like this:
>
> (05/25/06 00:00:00)     NA     NA  NA
> (05/25/06 00:02:00) 948.20 24.198   0
> (05/25/06 00:04:00) 948.26 20.640   0
> (05/25/06 00:06:00) 948.37 19.653   0
> (05/25/06 00:08:00) 948.48 19.135   0
> (05/25/06 00:10:00) 948.54 22.510   0
> (05/25/06 00:12:00) 948.55 27.175   0
> (05/25/06 00:14:00) 948.46 30.075   0
> (05/25/06 00:16:00) 948.59 28.815   0
> (05/25/06 00:18:00) 948.96 27.938   0
>
> old spans a larger range of dates than new.  I would like to take all the values in new that are not NA and place them in old, matching the time indices.  I have tried a number of variations on the themes of merge and replace, but can't get them to work, and the brute force for loop solution is unnacceptably slow.  Could someone suggest a solution?
>
> Many thanks,
> Tim
>
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