[R] R-ish challenge for dependent ranking
jim holtman
jholtman at gmail.com
Mon Aug 25 18:31:32 CEST 2008
If you want to put it back in the original data frame:
> ds= data.frame( xn=rnorm(32), yn=rnorm(32), zn=rnorm(32) )
> ds$drank1group= as.integer((rank( ds$xn )-1)/4) # ok, the first set
> ds$drank2group <- ave(ds$yn, ds$drank1group, FUN=rank)
> ds
xn yn zn drank1group drank2group
1 -1.27659221 -0.68166048 0.42510038 0 1
2 -0.57326541 -0.32427027 -0.23864710 1 3
3 -1.22461261 0.06016044 1.05848305 0 3
4 -0.47340064 -0.58889449 0.88642265 2 1
5 -0.62036668 0.53149619 -0.61924305 1 4
6 0.04211587 -1.51839408 2.20610246 5 3
7 -0.91092165 0.30655786 -0.25502703 0 4
8 0.15802877 -1.53644982 -1.42449465 5 2
9 -0.65458464 -0.30097613 -0.14439960 0 2
10 1.76728727 -0.52827990 0.20753834 7 3
11 0.71670748 -0.65209478 2.30797840 6 1
12 0.91017423 -0.05689678 0.10580237 6 3
13 0.38418536 -1.91435943 0.45699881 5 1
14 1.68217608 1.17658331 -0.07715294 7 4
15 -0.63573645 -1.66497244 -0.33400084 1 1
16 -0.46164473 -0.46353040 -0.03472603 2 2
17 1.43228224 -1.11592011 0.78763961 7 1
18 -0.65069635 -0.75081900 2.07524501 1 2
19 -0.20738074 2.08716655 1.02739244 3 4
20 -0.39280793 0.01739562 1.20790840 2 4
21 -0.31999287 -1.28630053 -1.23132342 3 3
On Mon, Aug 25, 2008 at 11:42 AM, baptiste auguie <ba208 at exeter.ac.uk> wrote:
> Hi
>
>
> I think you want something like,
>
>> with(ds, tapply(yn, drank1group, rank) )
>
> also, the reshape package should do this sort of thing neatly.
>
> Hope this helps,
>
> baptiste
>
> On 25 Aug 2008, at 16:10, ivo welch wrote:
>
>> Dear R wizards: First, thanks for the notes on SQL. These pointers
>> will make it a lot easier to deal with large data sets. Sorry to
>> have a second short query the same day. I have been staring at this
>> for a while, but I cannot figure out how to do a dependent ranking the
>> R-sh way.
>>
>> ds= data.frame( xn=rnorm(32), yn=rnorm(32), zn=rnorm(32) )
>> ds$drank1group= as.integer((rank( ds$xn )-1)/4) # ok, the first set
>> of 8 groups, each with 4 elements
>>
>> ds$drank2.bydrank1group= ??? ## here I want within each drank1group
>> the rank based on yn (from 1 to 4)
>>
>> something like "by(ds,drank1group, rank(ds$yn))". obviously, this
>> neither works nor has same dimensional output.
>>
>> of course, there is a really simple, clever way to do this in
>> R...except that it totally eludes me. before I start writing a hand
>> iterating function, could someone please let me know how to do this?
>>
>> regards,
>>
>> /iaw
>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> _____________________________
>
> Baptiste Auguié
>
> School of Physics
> University of Exeter
> Stocker Road,
> Exeter, Devon,
> EX4 4QL, UK
>
> Phone: +44 1392 264187
>
> http://newton.ex.ac.uk/research/emag
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
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