[R] formatting a list

[jim holtman]

What is it that you want to do?  The 'scan' statement give you a list
of length 7000 with 19 entries each.  Do you want to create a matrix
that has 7000 rows by 19 columns?  If so, then you just have to take
the output of the 'scan' and do:

x.matrix <- do.call('rbind', x)  # gives 7000 x 19 matrix.

So I am still not sure exactly what your input is and what you want to
do with it.

On 10/21/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> Hi Jim,
>
> thanks a lot.  It works, however - my other problem is that I need to
> transpose the original table before reading it into the list because the
> data come from Excel and it can't handle 7000 columns.  I could read it
> in R transpose end write into a new tab delim file and then read it back
> in,  but I would think that there might be a way in R to do both.
> Would you know about the way?
>
> Tomas
>
> jim holtman wrote:
> > another choice is:
> >
> > x <- scan('temp.txt', what=c(rep(list(0), 19)))
> >
> > On 10/20/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> >
> >> Hi,
> >>
> >> I am new to R and need to read in a file with 19 columns and 7000 rows
> >> and make it into a list of 7000 lists with 19 items each.  For a
> >> simpler case of 10 by 10 table I used x <-scan("file",
> >> list(0,0,0,0,0,0,0,0,0,0)), perhaps clumsy, but it did the job.
> >> However with the large 19x7000 (which needs to be transposed) I am not
> >> sure how to go about it.
> >>
> >> Coudl somebody suggest a way?
> >>
> >> Thanks,
> >>
> >> Tomas
> >>
> >> ______________________________________________
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> >> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> >> and provide commented, minimal, self-contained, reproducible code.
> >>
> >>
> >
> >
> >
>


-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?