[R] vector sprintf argument

[Moshe Olshansky]

The only thing I can think of is:

> a <- c(1,2.7,5.19)
> F<-c("numeric:  %d ","%g ","%8.3f")
> x<-sapply(1:length(a),function(i)
sprintf(F[i],a[i]))
> y<-paste(x,sep="",collapse="")

But I am sure that you will get a better advice
elsewhere.

--- Tom Sgouros <tomfool at as220.org> wrote:

> 
> Hello all:
> 
> If I have a vector and a format, I want to do this:
> 
>  > A <- c(3,4,5)
>  > F <- "Number: %d, %d, %d"
>  > sprintf(F,A)
> 
> This doesn't work because A isn't three arguments,
> it's just one.  Is
> there a way to peel the vector members out of A so
> that sprintf can get
> at them?
> 
> I would like to do this because I have a large set
> of variable-length
> data that I'd like to print out in fancy formatted
> form.  The vectors
> range in length from 2 to 7.  Each row is different,
> so I had been
> hoping to do this with an array of formats, too.
> 
> I feel like I'm either overlooking something
> obvious, or have determined
> to do this in an un-R fashion.  Any advice is
> welcome.  (On this topic,
> that is.)
> 
> Many thanks,
> 
>  -tom
> 
> 
> -- 
>  ------------------------
>  tomfool at as220 dot org
>  http://sgouros.com  
>  http://whatcheer.net
> 
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