[R] How to convert List object to function arguments?

[Shiazy]

Dear R gurus,

I have a function "goftests" that receives the following arguments:
* a vector "x" of data values;
* a distribution name "dist";
* the dots list ("...") containing a list a parameters to pass to CDF 
function;
and calls several goodness-of-fit tests on the given data values against 
the given distribution.
That is:

##### BEGIN CODE SNIP #####

# Covert a distribution name to the related CDF function name
distname2cdfname <- function( dist )
{
   if ( dist == "beta" ) { return( "pbeta" ); }
   if ( dist == "cauchy" ) { return( "pcauchy" ); }

   # many other and personalized (e.g. pareto, ...) distributions ...

   return( "" ); # fall-back case
}

# Performs some GoF tests (KS, Chi-Square, Anderson-Darling,...)
# (the "..." list contains parameters for CDF function)
goftests <- function( x, dist, ... )
{
   cdfname <- distname2cdfname( dist );
   res$ks <- ks.test( x, cdfname, ... );
   # res$chisq <- ...
   # res$anddarl <- ...

   return( res )
};

##### END CODE SNIP #####

So the problem is passing "..." to CDF function (for instance, see 
ks.test above) in the "right form". The "..." is passed (to "goftests") 
as a list object and it should be converted to an "argument list".
For instance:

##### BEGIN CODE SNIP #####

parms <- list( shape1 = 2, shape2 = 5 );
goftests( x, "beta", parms[["shape1"]], parms[["shape2"]] ); # Works!
goftests( x, "beta", parms ) # Don't Works!

parms <- list( aNum = 5, aVector = c(1,2,3), aMatrix = 
matrix(c(4,5,6,7,8,9),nrow=2,byrow=T) );
goftests( x, "my-special-distr", parms[["aVector"]], parms[["aMatrix"]], 
parms[["aNumber"]] ); # Works!
goftests( x, "my-special-distr", parms ) # Don't Works!

##### END CODE SNIP #####

Obviously I have to use the "don't work" form.

How can I do this in R (if possible)?

Thank you very much in advance!

Best regards,

-- Marco