[R] approx with ties = 'ordered'
Vadim Ogranovich
vograno at yahoo.com
Mon Apr 2 23:37:05 CEST 2007
Hi,
I am a bit surprised how approx resolves ties when ties = 'ordered'. In the
following two examples I'd expect the first expression to return 1 (not 2).
The documentation reads that "that 'f=0' is right-continuous and 'f=1' is
left-continuous" so one would expect the argument to matter when resolving ties.
Thanks,
Vadim
-> approx(c(1,1), seq(2), 1, method = "const", rule = 2, f = 1, yleft = NA, ties
= "ordered")$y
[1] 2
-> approx(c(1,1), seq(2), 1, method = "const", rule = 2, f = 0, yleft = NA, ties
= "ordered")$y
[1] 2
-> version
_
platform i486-pc-linux-gnu
arch i486
os linux-gnu
system i486, linux-gnu
status
major 2
minor 4.1
year 2006
month 12
day 18
svn rev 40228
language R
version.string R version 2.4.1 (2006-12-18)
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