[R] I think a simple question
Jeffrey Robert Spies
jspies at nd.edu
Sun Nov 12 23:31:27 CET 2006
tempin <- seq(1, 1411, by=30)
tempout <- array(data=NA, dim=length(tempin)*2)
tempout[seq(1,length(tempin)*2, by=2)]<-tempin
tempout[seq(2,length(tempin)*2, by=2)]<-tempin+5
Is this what you're looking for?
Jeff.
On Nov 12, 2006, at 5:20 PM, Leeds, Mark (IED) wrote:
> I have index ( of a vector ) values of say
>
> tempin<-c(1 31 61 91 121 all the way upto 1411)
>
> What I want is a function that takes in a number say, x = 5, and gives
> me an new vector
> of
>
> tempout<-1 6 31 36 91 96 121 126 .......... 1411 1416
>
> This can't be so hard but I can't get it and I've honestly tried.
> Obviously, tempin + 5 gives me the missing values but I don't know how
> to interwine them in the order above. Thanks for any help
> you can provide.
>
> mark
> --------------------------------------------------------
>
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>
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