[R] subsetting a matrix and filling other
Christos Hatzis
christos at nuverabio.com
Tue Nov 7 20:10:44 CET 2006
Use a list to store the partial matrices:
z <- vector("list", 189)
for(i in 1:189)
z[[i]] <- subset(...)
-Christos
-----Original Message-----
From: r-help-bounces at stat.math.ethz.ch
[mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of antonio rodriguez
Sent: Tuesday, November 07, 2006 2:01 PM
To: R-Help
Subject: [R] subsetting a matrix and filling other
Hi,
Having a matrix F(189,6575) I want to do this:
z1<-subset(F[,1], F[,1] >= 5 & F[,1] <= 10) .
.
.
z189<-subset(F[,189], F[,189] >= 5 & F[,189] <= 10)
I would prefer to have an empty matrix, say 'z' in order to fill its columns
with the output of subsetting F. But each of the subsets can differ in
length. It's to say:
length(z1)
1189
length(z2)
1238
Don't know how to set up this with a for loop or the use of apply:
z<-189
for (i in 1:189)
{z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
Error in z[i] <- subset(F.zoo[, i], F.zoo[, i] >= 5 & z1 <= 10) :
nothing to replace with
or
z<-matrix(0,6575,189)
for (i in 1:189)
{z[i]<-subset(F.zoo[,i], F.zoo[,i] >= 5 & z1 <= 10)}
new error
Thanks,
Antonio
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