[R] strange algorithm needed
Dimitris Rizopoulos
dimitris.rizopoulos at med.kuleuven.be
Wed Nov 1 15:51:56 CET 2006
probably you want to use the 'length' argument of rep(), e.g.,
rep(1:3, length = 17)
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: <Mark.Leeds at MorganStanley.com>
To: <r-help at stat.math.ethz.ch>
Sent: Wednesday, November 01, 2006 3:36 PM
Subject: [R] strange algorithm needed
>
>
> i need a strange algorithm that i can easily do in a loop but need
> o do without looping.
>
> suppose i have a vector of length y filled with zeros and a number
> x.
>
> then, i want a new vector which is
> (1,......x,1......x,1.....x,1.....y mod
> x )
>
> so if y was of length 17 and x was 3, the resultant vector should be
>
> (1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2)
>
> so basically , the algorithm should repeat seq(1,x) as many times as
> needed to fill y but
> then , if the last one doesn;'t fit perfectly, it should stop
> whenever it
> hits the end of y ?
>
> rep(seq(1:x,length(y)/x) will work when there is a perfect fit but
> it can't handle the non fit cases. it just cuts
> off the non integer part of length(y)/x and then fills the vector
> do that the resultant vector is less than the length of y.
>
> thanks.
>
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