[R] strange algorithm needed

Dimitris Rizopoulos dimitris.rizopoulos at med.kuleuven.be
Wed Nov 1 15:51:56 CET 2006

probably you want to use the 'length' argument of rep(), e.g.,

rep(1:3, length = 17)

I hope it helps.


Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/

----- Original Message ----- 
From: <Mark.Leeds at MorganStanley.com>
To: <r-help at stat.math.ethz.ch>
Sent: Wednesday, November 01, 2006 3:36 PM
Subject: [R] strange algorithm needed

> i need a strange algorithm that i can easily do in a loop but need
> o do without looping.
> suppose i have a vector of length y filled with zeros and a number 
> x.
> then, i want a new vector which is 
> (1,......x,1......x,1.....x,1.....y mod
> x )
> so if y was of length 17 and x was 3, the resultant vector should be
> (1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2)
> so basically , the algorithm should repeat seq(1,x) as many times as
> needed to fill y but
> then , if the last one doesn;'t fit perfectly, it should stop 
> whenever it
> hits the end of y ?
> rep(seq(1:x,length(y)/x) will work when there is a perfect fit but
> it can't handle the non fit cases. it just cuts
> off the non integer part of length(y)/x and then fills the vector
> do that the resultant vector is less than the length of y.
> thanks.
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide 
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.

Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm

More information about the R-help mailing list