[R] appending

[Martin Henry H. Stevens]

Hi David,
It would be helpful if you supply a little data, upon which this  
would operate.
Hank
On Jun 14, 2006, at 12:31 PM, Afshartous, David wrote:

>  All,
>
> In the function below I have 24 individuals and 6 calculations per
> individual.
> The 6 calculations are collected each time in a 1:24 loop when
> calculating "delta".
>
> I'd like to collect all 144 = 24*6 calculations in one vector
> ("delta.patient.comb").
> The function works as is via indexing, but is there an easier way to
> collect the measurements via appendinng the 6 measurements each  
> time to
> the current set?  I couldn't find anything in Intro to R on appending.
>
> cheers,
> Dave
> ps - please respond directly to afshar at miami.edu
>
>
>
> creatine.function.new = function(delta.0.Y.0, gamma, comp.LIS.frm,
> comp.CAND.frm) { ## function to calcuate the delta.i, i.e. the percent
> ## leftover ## gamma = rate of Cr going into bucket, e.g., mg/hr ##
> delta.0.Y.0 = product of delta.0 and Y.0 at baseline ##
> Y.1 = delta.0.Y.0 + gamma
> delta = numeric(6)
> delta.patient = numeric(24)
> delta.patient.comb = numeric(144)
> ##
> 	for (k in 1:24) {		## each patient
> 		patient.k.CAND = which(comp.CAND.frm$Patient_no == k)
> 		Ucr.CAND.patient.k = comp.CAND.frm$Ucr[patient.k.CAND]
> 		C = Ucr.CAND.patient.k  ## 6 observed creatanine values
> for each patient
> 		delta[1] = (Y.1 - C[1])/Y.1
> 		Y.i = Y.1
> 		delta.i = delta[1]
> 		for (i in 1:5) {		## six measurments per
> patient
> 			Y.i.plus.1 = delta.i * Y.i + gamma
> 			delta.i.plus.1 = (Y.i.plus.1 -
> C[i+1])/Y.i.plus.1
> 			delta[i+1] = delta.i.plus.1
> 			delta.i = delta[i+1]
> 			Y.i = Y.i.plus.1
> 		}
> 		delta.patient[k] = list(delta)	
> 		delta.patient.comb[(6*(k-1)+1):(6*(k-1)+ 6)] = delta
> 	}
> list(delta.patient, delta.patient.comb)
> }
>
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Dr. M. Hank H. Stevens, Assistant Professor
338 Pearson Hall
Botany Department
Miami University
Oxford, OH 45056

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