[R] function parameters - testing
Gabor Grothendieck
ggrothendieck at gmail.com
Fri Jun 9 22:10:35 CEST 2006
x exists within the function f so the first print is TRUE;
however, exists does not try to evaluate it. is.null
does try to evaluate it and so at that point it discovers
the error.
Perhaps you want this:
f <- function(x) if (exists(deparse(substitute(x)))) print(is.null(x))
else print("none")
if (exists("z")) rm(z)
f(z) # "none"
z <- 3
f(z) # FALSE
z <- NULL
f(z) # TRUE
On 6/9/06, Larry Howe <linux at comjet.com> wrote:
> Hello,
>
> I am trying to test a function argument to see if it is or is not a useful
> number. However I cannot seem to find a test that works. For example
>
> > f = function(x) {
> + print(exists("x"))
> + print(is.null(x))
> + }
> >rm(x)
> > f(z)
> [1] TRUE
> Error in print(is.null(x)) : Object "z" not found
>
> exists gives TRUE, but then any other kind of test I try to run gives me an
> error. I need a test for existence that will work inside a function.
>
> Larry Howe
>
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