[R] formatting results from a function argument
Gabor Grothendieck
ggrothendieck at gmail.com
Mon Feb 20 13:42:08 CET 2006
Not sure I followed what it is you want but perhaps this will
help:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/67519.html
On 2/20/06, matgopa1 at umbc.edu <matgopa1 at umbc.edu> wrote:
> Hello all,
>
> I have a simple function which calculates summary statistics of a dataset
> in terms of a factor (say area).
>
> > x = data.frame(Area = c(rep("cleanup", 5), rep("ref", 5)), TcCB =
> c(rnorm(5)+2, rnorm(5)));x
> Area TcCB
> 1 cleanup 2.5829747
> 2 cleanup 2.6796868
> 3 cleanup 2.5437094
> 4 cleanup 2.8453616
> 5 cleanup 1.1789683
> 6 ref 1.0140391
> 7 ref -0.8433729
> 8 ref 0.6512422
> 9 ref 0.2341083
> 10 ref -0.2688026
> >
> > summarystat<-function(x)
> + {
> + no.samples<-by(x,x$Area,function(x) length(x$TcCB))
> + mean<-by(x,x$Area,function(x) mean(x$TcCB))
> + quantile<-by(x,x$Area,function(x) summary(x$TcCB))
> + stdev<-by(x,x$Area,function(x) sd(x$TcCB))
> + final<-do.call("cbind",c(quantile,mean,stdev,no.samples))
> + return(final)
> + }
> >
> > test<-summarystat(x);test
>
> cleanup ref cleanup ref cleanup ref cleanup ref
> Min. 1.179 -0.8434 2.36614 0.1574428 0.6737748 0.736001 5 5
> 1st Qu. 2.544 -0.2688 2.36614 0.1574428 0.6737748 0.736001 5 5
> Median 2.583 0.2341 2.36614 0.1574428 0.6737748 0.736001 5 5
> Mean 2.366 0.1574 2.36614 0.1574428 0.6737748 0.736001 5 5
> 3rd Qu. 2.680 0.6512 2.36614 0.1574428 0.6737748 0.736001 5 5
> Max. 2.845 1.0140 2.36614 0.1574428 0.6737748 0.736001 5 5
> >
>
> Now the results are arranged as per quantile function.
>
> When the results are printed, I would like to have the results for mean,
> stdev, no.samples, quantiles one after the other with the function names
> for the two factors namely cleanup and reference. Can somebody help in
> doing so? I did refer to a previous thread on formatting results from
> function. But my case is little different.
>
> Moreover, i would like to know, if there is any R command which produces
> this general summary statistics as above?
>
> Thanks for your time.
> Mathangi
>
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