[R] Choices from a matrix

[Berton Gunter]

Quite right (ALWAYS TEST, Bert!), because expand.grid() returns a
data.frame. But all you have to do is create newX as a data.frame:

newX<-data.frame(matrix(0, ncol=ncol(X),nrow=2^length(I)))

and **now** it will work:

>X<-matrix(1:6,nr=2)
>I<- c(1,3)
>newX<-data.frame(matrix(0, ncol=ncol(X),nrow=2^length(I)))
>newX[,I]<-expand.grid(as.list(as.data.frame(X[,I])))
>newX

  X1 X2 X3
1  1  0  5
2  2  0  5
3  1  0  6
4  2  0  6

Note that newX is a data.frame -- you may wish to recast it as a matrix. Of
course, I'm still not sure that this is what you wanted.

-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
 
"The business of the statistician is to catalyze the scientific learning
process."  - George E. P. Box
 
 

> -----Original Message-----
> From: bgunter 
> Sent: Friday, May 06, 2005 12:49 PM
> To: davidr at rhotrading.com; r-help at stat.math.ethz.ch
> Subject: RE: [R] Choices from a matrix
> 
> If I understand you correctly, here's one way based on expand.grid().
> 
> I is just an index set, and so all you really need to do is 
> generate your 2^k rows from the part of the matrix you're 
> using in the right places via replacement:  
> 
> e.g. newX<-matrix(0, ncol=ncol(X),nrow=2^length(I))
> newX[,I]<-expand.grid(as.list(as.data.frame(X[,I]))) 
> 
> 
> N.B. I tried to do the this without the explicit as.list() 
> cast, but got an error message. I would have thought that 
> expand.grid should have recognized that a data.frame IS a 
> list without the cast.
> 
> -- Bert Gunter
> Genentech Non-Clinical Statistics
> South San Francisco, CA
>  
> "The business of the statistician is to catalyze the 
> scientific learning process."  - George E. P. Box
>  
>  
> 
> > -----Original Message-----
> > From: r-help-bounces at stat.math.ethz.ch 
> > [mailto:r-help-bounces at stat.math.ethz.ch] On Behalf Of 
> > davidr at rhotrading.com
> > Sent: Friday, May 06, 2005 12:06 PM
> > To: r-help at stat.math.ethz.ch
> > Subject: [R] Choices from a matrix
> > 
> > Could someone please suggest a more clever solution to the 
> > following problem than my loop below?
> > 
> > Given X a 2xN matrix X, and I a k-subset of N, 
> > Generate the (2^k)xN matrix Y with columns not in I all zero 
> > and the other columns with all choices of an entry from the 
> > first or second row of X.
> > 
> > For example, with
> > X <- matrix(1:8, nrow=2)
> > I <- c(1,3)
> > 
> > X is
> > 1 3 5 7
> > 2 4 6 8
> > 
> > and Y should be
> > 1 0 5 0
> > 2 0 5 0
> > 1 0 6 0
> > 2 0 6 0
> > 
> > The order of the rows is unimportant.
> > ---
> > I solved this using a loop over the rows of Y after forming 
> > some preliminary matrices. I think it could be improved.
> > 
> > N <- NCOL(X)
> > k <- length(I)
> > G <- as.matrix(expand.grid(rep(list(c(1,2)),k)))
> > Y <- matrix(0,nc=N,nr=NROW(G))
> > 
> > for(i in 1:NROW(G)){
> >    ind <- rep(1,N)
> >    ind[I] <- G[i,]
> >    Y[i,] <- X[array(c(ind,1:N),dim=c(N,2))]
> > }
> > Y[,-I] <- 0
> > 
> > 
> > 
> > 
> > David L. Reiner
> >  
> > Rho Trading
> > 440 S. LaSalle St -- Suite 620
> > Chicago  IL  60605
> >  
> > 312-362-4963 (voice)
> > 312-362-4941 (fax)
> >  
> > 
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