[R] tapply and NA value

[Dimitris Rizopoulos]

you should look at the 'na.rm=FALSE' argument of '?mean()', i.e.,

x <- rnorm(100); x[sample(100, 10)] <- NA
f <- sample(letters[1:5], 100, TRUE)
###############
tapply(x, f, mean)
tapply(x, f, mean, na.rm=TRUE)


I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/16/336899
Fax: +32/16/337015
Web: http://www.med.kuleuven.ac.be/biostat/
     http://www.student.kuleuven.ac.be/~m0390867/dimitris.htm


----- Original Message ----- 
From: "Leonardo Lami" <lami at faunalia.it>
To: <r-help at stat.math.ethz.ch>
Sent: Friday, March 25, 2005 10:35 AM
Subject: [R] tapply and NA value


> Hi,
> I'm writing for a little help.
> I have a dataframe with same NA value and I'd like to obtain the 
> means of the
> value of a coloumn grouped by the levels of a factor coloumn of the 
> datframe.
> I'm using the function "tapply" but I see that if only a NA value is 
> present
> the result is NA.
> There is an option to have the correct result or I must use an other 
> function?
>
> Thanks of all
> Leonardo
> -- 
> Leonardo Lami
> lami at faunalia.it            www.faunalia.it
> Via Colombo 3 - 51010 Massa e Cozzile (PT), Italy   Tel: 
> (+39)349-1310164
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> https://www.biglumber.com
>
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