[R] Trim function ?
ripley@stats.ox.ac.uk
ripley at stats.ox.ac.uk
Thu May 9 18:09:51 CEST 2002
On 9 May 2002, Douglas Bates wrote:
> Ernesto Jardim <ernesto at ipimar.pt> writes:
>
> > Hi
> >
> > I've imported some data from a oracle database and the strings have a
> > lot of blank space (because of the delimiter). I want to remove these
> > blanks space with something similar to a trim function.
> >
> > I don't find a trim function or something similar. Can someone give a
> > help on this ?
>
> If you want to remove trailing blanks you can use sub with the regular
> expression ' +$'.
>
> > str = 'Now is the time '
> > sub(' +$', '', str, extended = TRUE)
> [1] "Now is the time"
>
> I had hoped you could use '\s+$' or '\\s+$' but that doesn't seem to
> work. I guess we would need the perl regular expression library, of
> which there has been some discussion, to do that.
In today's R-devel
> sub('\\s+$', '', str, perl = TRUE)
[1] "Now is the time"
but as it was literally added a few hours ago, don't expect it to have
bedded down yet. (I have support under Windows, but no connectivity to
commit it at present.)
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272860 (secr)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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