[R] Breakdown of Treatment Sum of Squares

Wendy Catchpole w.catchpole at adfa.edu.au
Tue Mar 12 02:24:11 CET 2002

When using an ordered factor in aov, how do I break the treatment sum of 
into all its separate degrees of freedom? In other words can I use contr.poly
in aov to get the full breakdown of the treatment sum of squares?

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