[R] inclusion criteria help

Thomas Lumley tlumley at u.washington.edu
Tue Nov 27 20:24:45 CET 2001

On Tue, 27 Nov 2001, Aaron J Mackey wrote:

> On Tue, 27 Nov 2001, Thomas Lumley wrote:
> > Actually, which.max already does break ties -- it finds the first maximum.
> Sorry, what I meant was: if there are ties, I want to apply additional
> logic to decide which is the right row to return (i.e. I may not want the
> first row that has the maximum coverage).  I may want to break ties by
> finding the row with the minimal "percid" or some other calculated value.
> I think it might end up looking something like this:
> filter <- function(this.subset) {
>    best <- which(this.subset$coverage == max(this.subset$coverage))
>    best <- which(this.subset$percid[best] == min(this.subset$percid[best]))
>    # any additional logic to narrow down best to the absolute best row index
>    # now return the first best row:
>    this.subset[best[1], , drop=FALSE]
> }

Yes, exactly like that,  though you wouldn't need the drop=FALSE in this
context (it's harmless).


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