R-beta: CI for median in funtion boxplot

[Peter Dalgaard BSA]

Rick White <rick at stat.ubc.ca> writes:

> 
> I noticed that boxplot computes a 95% CI for the median by using
> median +/- 1.58*IQR./sqrt(n)
> 
> Where does the 1.58 constant come from?
> 

Search me... However, wouldn't it be better in any case to do an exact
95% CI based on the binomial distribution? Of course, you need at
least 6 observations to do that.

-- 
   O__  ---- Peter Dalgaard             Blegdamsvej 3  
  c/ /'_ --- Dept. of Biostatistics     2200 Cph. N   
 (*) \(*) -- University of Copenhagen   Denmark      Ph: (+45) 35327918
~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk)             FAX: (+45) 35327907

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